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We use an integral representation for the elliptic function:
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Then![]()
Now we use Mathematica to do the double integration.
It immediately follows that![]()
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We consider the more general integral
, where
is an arbitrary parameter. We can evaluate this integral with Mathematica.
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To find the original integral we need to find the limit of this expression as
tends to 0. This in turn means that we need to find the asymptotic expansion of
. For that we convert the hypergeometric function into a series and look at the general term.
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We expand this into a series with respect to
around zero.
Now we sum the series with this as the general term.
Finally, in the result of the integration at the beginning, we replace
by this asymptotic expansion.
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The direct approach does not work.
We observe that
.
Substitute this into the series and change the order of summation and integration.![]()
We evauate the series and integral on the right side with Mathematica and then form the original expression.
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