Wolfram ResearchPRODUCTSPURCHASEFOR USERSCOMPANYOUR SITES
THIS IS DOCUMENTATION FOR AN OBSOLETE PRODUCT.
SEE THE DOCUMENTATION CENTER FOR THE LATEST INFORMATION.
Previous section-----Next section

3.1.7 Advanced Topic: Interval Arithmetic

Interval[{min, max}] the interval from min to max
Interval[{ ,  }, { ,  }, ... ]
the union of intervals from  to  ,  to  , ...

Representations of real intervals.
This represents all numbers between  and  .

In[1]:=  Interval[{-2, 5}]

Out[1]=

The square of any number between  and  is always between 0 and 25.

In[2]:=  Interval[{-2, 5}]^2

Out[2]=

Taking the reciprocal gives two distinct intervals.

In[3]:=  1/Interval[{-2, 5}]

Out[3]=

Abs folds the intervals back together again.

In[4]:=  Abs[%]

Out[4]=

You can use intervals in many kinds of functions.

In[5]:=  Solve[3 x + 2 Equal Interval[{-2, 5}], x]

Out[5]=

Some functions automatically generate intervals.

In[6]:=  Limit[Sin[1/x], x -> 0]

Out[6]=

IntervalUnion[ ,  , ... ]
find the union of several intervals
IntervalIntersection[ ,  , ... ]
find the intersection of several intervals
IntervalMemberQ[interval, x] test whether the point x lies within an interval
IntervalMemberQ[ ,  ] test whether  lies completely within

Operations on intervals.
This finds the overlap of the two intervals.

In[7]:=  IntervalIntersection[Interval[{3, 7}], Interval[{-2, 5}]]

Out[7]=

You can use Max and Min to find the end points of intervals.

In[8]:=  Max[%]

Out[8]=

This finds out which of a list of intervals contains the point 7.

In[9]:=  IntervalMemberQ[
Table[Interval[{i, i+1}], {i, 1, 20, 3}], 7]

Out[9]=

You can use intervals not only with exact quantities but also with approximate numbers. Even with machine-precision numbers, Mathematica always tries to do rounding in such a way as to preserve the validity of results.

This shows explicitly the interval treated by Mathematica as the machine-precision number 0.

In[10]:=  Interval[0.]

Out[10]=

This shows the corresponding interval around 100., shifted back to zero.

In[11]:=  Interval[100.] - 100

Out[11]=

The same kind of thing works with numbers of any precision.

In[12]:=  Interval[N[Pi, 50]] - Pi

Out[12]=

With ordinary machine-precision arithmetic, this computation gives an incorrect result.

In[13]:=  Sin[N[Pi]]

Out[13]=

The interval generated here, however, includes the correct value of 0.

In[14]:=  Sin[Interval[N[Pi]]]

Out[14]=


Any questions about topics on this page? Click here to get an individual response.Buy NowFree TrialMore Information



 © 2009 Wolfram Research, Inc.  Terms of Use  Privacy Policy |
Sign up for our newsletter: